Problem Solving Involving Inequalities

Problem Solving Involving Inequalities-37
We solve the inequality by dividing both sides by 4.50: x ≥ 144.44. What must the length be if the perimeter is at least 180 inches? The formula for perimeter is: Perimeter = 2 x length 2 x width Since the perimeter must be at least 180 inches, we have 2x 2(20) ≥ 180.We round up the answer to 145 since only whole boxes can be sold. Check If we multiply 145 by .50 we obtain 2.50, so if Virenas troop sells more than 145 boxes they will raise more than 0.

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He sold 85 subscriptions in the first three weeks of the month.

How many subscriptions must Leon sell in the last week of the month?

Because by moving the smaller term, I was able to avoid having a negative coefficient on the variable, and therefore I was able to avoid having to remember to flip the inequality when I divided off that coefficient.

I find it simpler to work this way; I make fewer errors. Why did I switch the inequality in the last line and put the variable on the left?

Solve (Note the change in sense due to dividing by a negative number) Check: Always check your solution and you can be sure your answer is correct.

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In this case, any number less than `-6` should "work" in the original equation, and any number bigger than `-6` should fail.If you're seeing this message, it means we're having trouble loading external resources on our website.If you're behind a web filter, please make sure that the domains *.and *.are unblocked.But we need to be a bit more careful (as you will see). Are you ready to dive into the "real world" of inequalities?We solve the inequality by subtracting 85 from both sides: x ≥ 35.Check To check the answer, we see that 85 35 = 120.(See Solving Equations.) We need to be careful about the sense of the equality when multiplying or dividing by negative numbers.Following are several examples of solving equations involving inequalities. but we must also pay attention to the direction of the inequality.Another thing we do is multiply or divide both sides by a value (just as in Algebra - Multiplying).


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