Physics Coursework Gcse Resistance Wire

Physics Coursework Gcse Resistance Wire-72
The number of electrons depends on the amount of electrons in the outer energy shell of the atoms, if there are more or larger atoms then there must be more electrons available.If the material has a high number of atoms there will be a high number of electrons causing a lower resistance because of the increase in the number of electrons.

The number of electrons depends on the amount of electrons in the outer energy shell of the atoms, if there are more or larger atoms then there must be more electrons available.If the material has a high number of atoms there will be a high number of electrons causing a lower resistance because of the increase in the number of electrons.How do I work out the resistivity using the equations in the red boxes? so, gradient of 0.1m length would be = 4.7x10^-7 / 2.6x10^-8 m^2 = 1.8..…

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We didn’t encounter any problems, and as far as seen so far there were no major problems at all.

Many steps could be made to make the results more accurate, and precise.

If the wire is heated up the atoms in the wire will start to vibrate because of their increase in energy.

This causes more frequent collisions between the electrons and the atoms as the atoms move into the path of the electrons.

I don't understand what its asking me to do, calculate the resistivity of a specific length or just one? The gradient of that group would be resisitivity divided by area, and you just times by area to get resisitivty.

How do I work out the resistivity using the equations in the red boxes? Well you can work out the resisitivity from just one length of wire, but I think the idea is that because it's an experiment, you should do many lengths of wire, measure the resistance and plot the graph shown (R vs L).When measuring the wire lengths for the experiment, we didn’t cut fairly, and we measured out approximate lengths roughly depending on a ruler that was quite a it away.One major improvement that would affect the results a lot would be to make these readings more accurate, this is because the length/width of the wire is THE MAIN variable of the experiment, and so if this is altered even by a extremely small amount, it would make a lot of a difference to the results. EDIT: For an ideal conductor, there is no resistance and hence no energy losses. For calculation purposes it can therefore be ignored. The word 'ideal' is another way of saying a resistance follows Ohms law without needing to invoke thermal considerations or any other parameter which would cause a deviation form Ohms law such as inductance, capacitance etc. The word 'ideal' is another way of saying the conductor follows Ohms law without needing to invoke thermal considerations or any other parameter which would cause a deviation form Ohms law such as inductance, capacitance etc. Following on from Physics Enemy, yes, that does imply that an 'ideal resistance' follows Ohms law perfectly and an 'ideal conductor' is perfect with no resistance and hence no energy losses.These collisions slow down the flow of electrons causing resistance.Resistance is a measure of how hard it is to move the electrons through the wire. The word 'ideal' is another way of saying the conductor follows Ohms law without needing to invoke thermal considerations or any other parameter which would cause a deviation form Ohms law such as inductance, capacitance etc.Before starting my coursework I have decided to choose 2 factors that will affect the resistance of a wire. The gradient of that group would be resisitivity divided by area, and you just times by area to get resisitivty. Well you can work out the resisitivity from just one length of wire, but I think the idea is that because it's an experiment, you should do many lengths of wire, measure the resistance and plot the graph shown (R vs L).

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